分解因式:(1)ax2-2ax+a(2)(x-1)(x-3)+1(3)x2(x-y)+(y-x)
题型:解答题难度:一般来源:不详
分解因式: (1)ax2-2ax+a (2)(x-1)(x-3)+1 (3)x2(x-y)+(y-x) |
答案
(1)ax2-2ax+a=a(x2-2x+1)=a(x-1)2;
(2)(x-1)(x-3)+1=x2-4x+3+1=x2-4x+4=(x-2)2;
(3)x2(x-y)+(y-x)=(x-y)(x2-1)=(x-y)(x+1)(x-1). |
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