(1)500 (2)由P = UI得,通过R1的电流为I1=P1 /U = 500 W /220 V= 2.3 A (3)①电饼铛消耗的电能为 W = 225r÷3000r/kW?h = 0. 075 kW?h ,电饼铛的实际功率为p实= W/t=0.075kw.h÷5/60h= 0.9 kW = 900 W②电饼铛的实际功率小于其额定功率(或电饼铛两端的实际电压小于其额定电压)
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