(1)1cm3中阴、阳离子总数=()3; 1cm3中 Ni2+-O2-离子对数=()3× 密度==()×74.7g/mol× | 6.02×1023/mol | =g/(cm)3 答:NiO晶体的密度为g/(cm)3; (2)设1mol Ni0.97O中含Ni3+xmol,Ni2+为(0.97-x)mol,根据晶体仍呈中性,可知 3x+2×(0.97-x)=2×1, x=0.06mol Ni2+为(0.97-x)mol=0.91mol,即离子数之比 Ni3+:Ni2+=0.06:0.91=6:91, 答:晶体中Ni3+与Ni2+的离子数之比为6:91. |