解:由A∩B=B得BA,而A={-4,0},△=当△=8a+8<0,即a<-1时,B=,符合BA;当△=8a+8=0,即a=-1时,B={0},符合BA;当△=8a+8>0时,即a>-1时,B中有两个元素,而BA={-4,0};∴B={-4,0}得a=1∴a=1或a≤-1
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