y=(1-Inx)/(1+Inx)的导数
题目
y=(1-Inx)/(1+Inx)的导数
答案
y=(1-Inx)/(1+Inx)
=(1+lnx-2lnx)/(1+lnx)
=1-2lnx/(1+lnx)
y'=-[(2/x)*(1+lnx)-2lnx(1/x)]/(1+lnx)^2;
=-2/[x(1+lnx)^2].
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