sin（x+y)=12,sin(x—y）=13,求[tan（x+y）-tanx-tany][tany的平方tan（x+y)]

题目

sin（x+y)=12,sin(x—y）=13,求[tan（x+y）-tanx-tany][tany的平方tan（x+y)]

答案

sin(x+y)=sinxcosy+cosxsiny=1/2 sin(x-y)=sinxconsy-cosxsiny=1/3 sinxcosy=5/12,cosxsiny=1/12 tanx/tany=sinxcosy/cosxsiny=5.[tan（x+y）-tanx-tany]/[tany的平方tan（x+y)] =[(tanx+tany)/(1-tanxtany)-(tanx+t...