1、用因式分解法解下列方程:

题目

1、用因式分解法解下列方程:
(1)3y^2-5y=0 （2）4x^2=12x (3)x^2+9=-6x (4)9x^2=(x-1)^2 (5) (x-2)(2x-3）=6
（6） x(x-4)= - 4 (7) (2x-1)^2= - 8 (8) (x-2)^2=2x(x-2)
2、解方程 x^2-2√3 x= - 3


求解、求详细答案.比如,
x^3-3x^2-13x+15
=x^3-3x^2+2x-15x+15
=x(x^2-3x+2)-15(x-1)
=x(x-2)(x-1)-15(x-1)
=(x-1)[x(x-2)-15]
=(x-1)[x^2-2x-15]
=(x-1)(x-5)(x+3) 这样的

答案

1.3y^2-5y=0 y(3y-5)=0y1=0,y2=3/52.4x^2=12x 4x²-12x=04(x²-3x)=0x(x-3)=0x1=0,x2=33.x^2+9=-6x x²+6x+9=0(x+3)²=0x=-34.9x^2=(x-1)^2 9x²-(x-1)²=0[3x+(x-1)][3x-(x-1)]=0(4x-1)(2x...