因式分解(x^2+1）×（3x-2）+（2x-3）（1+x^2) 化简求值[2x^2+(x+y)(x-y)]×[(x+y)^2+(x-y)^2] x=2 y=-1/2

题目

因式分解(x^2+1）×（3x-2）+（2x-3）（1+x^2) 化简求值[2x^2+(x+y)(x-y)]×[(x+y)^2+(x-y)^2] x=2 y=-1/2

答案

因式分解
(x^2+1）×（3x-2）+（2x-3）（1+x^2)
=(x²+1)(3x-2)+(2x-3)(x²+1)
=(x²+1)(3x-2+2x-3)
=5(x²+1)(x-1)

化简求值[2x^2+(x+y)(x-y)]×[(x+y)^2+(x-y)^2] 你的题目可能有一个字母写错了
=(2x²+x²-y²)(2x²+2y²)
=2(3x²-y²)(x²+y²)
当x=2 y=-1/2时
原式=2×(12-1/4)(4+1/4)
=799/8