从方程组4x-3y-3z=0,x-3y+z=0(xyz≠0),则x:z=__,y:z+___

题目

从方程组4x-3y-3z=0,x-3y+z=0(xyz≠0),则x:z=__,y:z+___

答案

4x-3y-3z=0,========>4x-3y=3z (1)
x-3y+z=0(xyz≠0),==>x-3y=-z (2)
(1)-(2)得
3x=4z,9y=7z
x:z=4:3
y:z=7:9