计算sin(-π+π/3)+tan(3π/2-π/6)+sin15,

题目

计算sin(-π+π/3)+tan(3π/2-π/6)+sin15,

答案

楼主题目中的角度有：-π+π/3、3π/2-π/6、15.前边的-π+π/3、3π/2-π/6,单位应该是弧度吧?那……后边的15,单位应该是什么呀?是弧度?还是度? sin(-π+π/3)+tan(3π/2-π/6)+sin15=sin(-2π/3)+tan(π+π/3)+sin...