含FeS2 80%的硫铁矿200t,灼烧时硫损失2%,能制98.3%的硫酸多少吨
题目
含FeS2 80%的硫铁矿200t,灼烧时硫损失2%,能制98.3%的硫酸多少吨
答案
200*80%*64/120=85.333吨硫损失2%=85.333*2%=1.706785.333-1.70667=83.626S+O2=SO22SO2+O2=2SO3H2O+SO3=H2SO42S+3O2+2H2O=H2SO4 64 98 83.626 X=128.053128.053/98.3%=130...
举一反三
我想写一篇关于奥巴马的演讲的文章,写哪一篇好呢?为什么好
最新试题
- 小明在计算除法时,把除数62写成26,结果得到商35还余20这到题的答案
- 举例说明怎样进行体积单位之间的换算
- at the most 和at most no more than 和 NOT MORE THAN 有什么区别呢?
- 学校买了3个篮球和7个排球,共花440 元,每个篮球比排球贵30元,篮球每个65元,排球每个35 元.
- She brought with her three friends,none of whom I had ever met before
- 修一条路,甲队独修需要10天完成,乙队独修需要15天完成,两队合修4天,可以修完成这条路的几分之几?
- Li Ming is very tired ___ too much homework.
- 如何提高英语文章阅读速度?
- He hurt （ ） when he fell off his bike 什么意思?
- [（2又2分之1）立方-（-1又2分之1）立方]除（5平方＋5乘3＋3的平方）＝
热门考点