已知4x²+y²-4x+10y+26=0,求12x+y的6次方根.

题目

已知4x²+y²-4x+10y+26=0,求12x+y的6次方根.

答案

4x^2+y^2-4x+10y+26=0,
4x^2-4x+1+y^2+10+25=0.
(2x-1)^2+(y+5)^2=0,
x=1/2,y=-5,
12x+y=1,
6次方根为1