求0度到360度的角x,已知 cos(3x+20度)=0.95

题目

求0度到360度的角x,已知 cos(3x+20度)=0.95

答案

cos(3x+20度)=0.953x+20度= 360度N +/- ARCCOS 0.953x = 360度N +/- ARCCOS 0.95-20度x= 120度N + (+/- ARCCOS0.95-20度 )/3代入N=0,1,2,3,...在 0度到360度内的有得 x= 119.398,107.268,239.398,227.268,359.398,34...