完全燃烧后的产物依次通过浓硫酸与NaOH溶液,分别增重5.4克与8.8克,可知n(H
2O)=
=0.3mol,
n(CO
2)=
=0.2mol,则有n(H)=0.6mol,m(H)=0.6g,n(C)=0.2mol,m(C)=0.2mol×12g/mol=2.4g,
则0.6g+2.4g=3.0g<4.6g,所以一定含有O元素,且m(O)=4.6g-3.0g=1.6g,n(O)=
=0.1mol.
所以:n(C):n(H):n(O)=0.2mol:0.6mol:0.1mol=2:6:1,
故该有机物的化学式为C
2H
6O,
故选D.