解不等式：7x^2+13x-2/(x+1)(x-2)>=0

题目

解不等式：7x^2+13x-2/(x+1)(x-2)>=0

答案

(7x^2+13x-2)/(x+1)(x-2)>=0
(7x-1)(x+2)/(x+1)(x-2)>=0
(x+1)(x-2)≠0,
x≠-1,x≠2
原不等式等则于：(7x-1)(x+2)(x+1)(x-2)>=0且x≠-1,x≠2
零点为：x=-2,-1,1/7,2
可得原不等式的解为：
x