若Ix+3I与I2y-3I互为相反数,求(x+y)除以(x-y)的直

题目

若Ix+3I与I2y-3I互为相反数,求(x+y)除以(x-y)的直

答案

Ix+3I+I2y-3I=0 x=-3,y=3/2 (x+y)除以(x-y)=1/3 互为相反数的两个数相加等于0 |x+3|+|2y-3|=0 因为|x+3|≥0,|2y-3|≥0 所以x+3=0,2y-3=0 求得,x=-3,y=1.5 (x+y)/(x-y)=(-3+1.5)/(-3-1.5)=(-1.5)/(-4.5)=1/3（答案是3...