计算①9√1/45÷3/2√3/5×1/2√2﹙2/3﹚

题目

计算①9√1/45÷3/2√3/5×1/2√2﹙2/3﹚
√6－1②﹙／3√√3／2－1／2√24﹚×﹙－2√6﹚③√8／3＋√1／2＋√0.125－√6＋√32④﹙3－√2﹚²﹙3＋√2﹚＋﹙3＋√2﹚²﹙3－√2﹚

答案

=-2√6^2-1/3√3/2*(-2√6)-1/2√24*(-2√6)
=-12+2/3√3/2*6+√24*6
=-12+2/3√9+√24*6
=-12+2/3*3+12
=2