设矩阵A=(0 1 2)(1 1 -1)(2 4 1)B=(2 -3)(1 5)(3 6 )解矩阵方程AX=次B

题目

设矩阵A=(0 1 2)(1 1 -1)(2 4 1)B=(2 -3)(1 5)(3 6 )解矩阵方程AX=次B

答案

(A,B)=0 1 2 2 -31 1 -1 1 52 4 1 3 6r3-2r20 1 2 2 -31 1 -1 1 50 2 3 1 -4r2-r1,r3-2r10 1 2 2 -31 0 -3 -1 80 0 -1 -3 2r1+2r3,r2-3r3,r3*(-1)0 1 0 -4 11 0 0 8 20 0 1 3 -2r1r21 0 0 8 20 1 0 -4 10 0 1 3 -2所...