2道gre数学题

题目

2道gre数学题
If r and s are positive intigers,each greater than 1,and if 11(s-1)=13(r-1),what is the least possible value of r+s?
A.2 B.11 C.22 D.24 E.26
Which of the following is equal to 1/4 of 0.01 percent?
A.0.000025 B.0.00025 C.0.0025 D.0.025 E.0.25

答案

1、r和s是大于1的整数,11(s-1)=13(r-1),那么11s+2=13r
最小的情况s=14,r=12,s+r=26,选E
2、0.01 percent是百分之0.01,也就是0.0001,它的四分之一就是0.000025,选A