290K,100Kpa时,已知；2H2O(g)=o2（g）+2H2(g)△H1 Cl2（g)+H2(g)=2Hcl(g△H2 2Cl(g)+2H2O(g)4Cl(g)+O2(g)

题目

290K,100Kpa时,已知；2H2O(g)=o2（g）+2H2(g)△H1 Cl2（g)+H2(g)=2Hcl(g△H2 2Cl(g)+2H2O(g)4Cl(g)+O2(g)
接上△H3 △H1与 △H2 和 △H3 之间的关系

答案

2H2O(g) = O2 (g) + 2H2(g) (1) △H1 Cl2(g) + H2(g) = 2HCl (g) (2) △H22Cl2 (g) + 2H2O (g) = 4HCl (g) + O2 (g) (3) △H3(1)+2*(2),两边消去H2,得到 (3) ,所以△H3 = △H1+2△H2