二元一次方程组7+x-3y/4=2x-y+5/3;10(x-y)-4(1-x)/3=y

题目

二元一次方程组7+x-3y/4=2x-y+5/3;10(x-y)-4(1-x)/3=y

答案

7+x-3y/4=2x-y+5/3;84+3(x-3y)=24x-4(y+5)84+3x-9y=24x-4y-2021x+5y=104 (1)10(x-y)-4(1-x)/3=y30(x-y)-4(1-x)=3y30x-30y-4+4x=3y34x-33y=4 (2)(1)*33+(2)*5得33*(21x+5y)+5*(34x-33y)=104*33+4*5693x+165y+170x-165...