行列式求解.0 1 2 -1 4 2 0 1 2 1 -1 3 5 1 2 3 3 1 2 1 2 1 0 3 5

题目

行列式求解.0 1 2 -1 4 2 0 1 2 1 -1 3 5 1 2 3 3 1 2 1 2 1 0 3 5
0 1 2 -1 4
2 0 1 2 1
-1 3 5 1 2
3 3 1 2 1
2 1 0 3 5

答案

r5-r2,r2-2r3,r4+3r3
0 1 2 -1 4
0 6 11 4 5
-1 3 5 1 2
0 12 16 5 7
0 1 -1 1 4
r4-2r2,r2-6r1,r5-r1
0 1 2 -1 4
0 0 -1 10 -19
-1 3 5 1 2
0 0 -6 -3 -3
0 0 -3 2 0
r4-2r5,r5-3r2
0 1 2 -1 4
0 0 -1 10 -19
-1 3 5 1 2
0 0 0 -7 -3
0 0 0 -28 57
r5-4r4
0 1 2 -1 4
0 0 -1 10 -19
-1 3 5 1 2
0 0 0 -7 -3
0 0 0 0 69
交换行(2次)
-1 3 5 1 2
0 1 2 -1 4
0 0 -1 10 -19
0 0 0 -7 -3
0 0 0 0 69
行列式 = -7*69 = -483.