当x=2,求1/x(x+2)+1/(x+2)*(x++4)+1/(x+4)*(x+6)+.+1/(x+98)*(x+100)的值
题目
当x=2,求1/x(x+2)+1/(x+2)*(x++4)+1/(x+4)*(x+6)+.+1/(x+98)*(x+100)的值
答案
1/x(x+2)+1/(x+2)*(x++4)+1/(x+4)*(x+6)+.+1/(x+98)*(x+100)=[2/x(x+2)+2/(x+2)*(x++4)+2/(x+4)*(x+6)+.+2/(x+98)*(x+100)]/2=[1/x-1/(x+2)+1/(x+2)-1/(x+4)+……+1/(x+98)-1/(x+100)]/2=[1/x-1/(x+100)]/2=(x+100-x...
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