|a-8b|+(4b-1)^2=0(a,b∈R),求log2（底数）a^b(真数)＝?

题目

|a-8b|+(4b-1)^2=0(a,b∈R),求log2（底数）a^b(真数)＝?

答案

|a-8b|+(4b-1)^2=0
所以a-8b=0,4b-1=0
b=1/4,a=2
log2(a^b)=log2[2^(1/4)]=1/4