若-|x+1|-(y-1)2=0,求x2005-y2004+x2003-y2002+…+x3-y2+x的值.
题型:解答题难度:一般来源:不详
若-|x+1|-(y-1)2=0,求x2005-y2004+x2003-y2002+…+x3-y2+x的值. |
答案
∵-|x+1|-(y-1)2=0, ∴-|x+1|=0,即x+1=0, 解得x=-1; y-1=0, 解得y=1; ∴x2005-y2004+x2003-y2002+…+x3-y2+x, =(-1)2005-12004+(-1)2003-12002+…+(-1)3-12+(-1), =-1-1-1-1-…-1-1-1, =-2005. |
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