计算(2ab2c5)4所得的结果是[ ]A.2ab2c20B.8a4b8c20C.8a4b6c9D.16a4b8c20
题型:单选题难度:简单来源:同步题
计算(2ab2c5)4所得的结果是 |
[ ] |
A.2ab2c20 B.8a4b8c20 C.8a4b6c9 D.16a4b8c20 |
答案
D |
举一反三
(-xm-1yn+1)3= |
[ ] |
A.-x3m-3y3n+3 B.x3m-3y3n+3 C.-x3m-1y3n+1 D.x3m-1y3n+1 |
如果a≠0,p是正整数,那么下列各式中错误的是 |
[ ] |
A.a-p= B.a-p= C.a-p=ap D.ap=(a-p)-1 |
已知x+y=a,试求(x+y)3(2x+2y)3(3x+3y)3的值。 |
若am=3,an=2,则am+n= |
[ ] |
A.5 B.6 C.8 D.9 |
x2n=2,则x6n= |
[ ] |
A.6 B.8 C.9 D.12 |
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