(12a2m+1bm+3-20am+1b2m+4+4am+1bm+2)÷4ambm+1=______.
题型:填空题难度:一般来源:不详
(12a2m+1bm+3-20am+1b2m+4+4am+1bm+2)÷4ambm+1=______. |
答案
(12a2m+1bm+3-20am+1b2m+4+4am+1bm+2)÷4ambm+1 =12a2m+1bm+3÷4ambm+1-20am+1b2m+4÷4ambm+1+4am+1bm+2÷4ambm+1 =3am+1b2-5abm+3+ab. |
举一反三
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计算:(a2b-ab2)÷(ab)=______. |
(x4y+6x3y2-x2y3)÷(3x2y)=______. |
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