解:(1)(π﹣3)0﹣+×(﹣1.5)2009 =1﹣2+()2008×(﹣1.5)2008×(﹣1.5) =﹣1﹣1.5 =﹣2.5; (2)2(a4)3+(﹣2a3)2·(﹣a2)3+a2a10 =2a12+4a6(﹣a6)+a12 =2a12﹣4a12+a12 =﹣a12; (3)∵2a(a﹣2b)﹣(a﹣2b)2 =2a2﹣4ab﹣(a2﹣4ab+4b2) =2a2﹣4ab﹣a2+4ab﹣4b2 =a2﹣4b2, 把a=,b=﹣,分别代入a2﹣4b2, ∴a2﹣4b2=()2﹣4()2=﹣4×=﹣. |