把下列各式分解因式(1)12a3b2-9a2b+3ab;(2)9x2-4y2;(3)x2(x-y)+(y-x);(4)(x-1)2+10(x-1)+25.
题型:解答题难度:一般来源:不详
把下列各式分解因式 (1)12a3b2-9a2b+3ab; (2)9x2-4y2; (3)x2(x-y)+(y-x); (4)(x-1)2+10(x-1)+25. |
答案
(1)12a3b2-9a2b+3ab=3ab(4a2b-3a+1);
(2)9x2-4y2=(3x+2y)(3x-2y);
(3)x2(x-y)+(y-x) =(x2-1)(x-y) =(x-y)(x+1)(x-1);
(4)(x-1)2+10(x-1)+25 =(x-1+5)2 =(x-4)2. |
举一反三
分解因式: (1)8a3b2-12ab3c+4abc (2)(x2-2x)2-1. |
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