由图可知: (1)AB段的路程: sAB=36.50cm-6.50cm=30.00cm=0.3m, 小球从A到B的时间: tAB=10h30min5s-10h29min55s=10s, 则小球在AB段的平均速度: vAB===0.03m/s; (2)AC段的路程: sAC=66.50cm-6.50cm=60.00cm=0.6m, 小球从A到C的时间: tAC=10h30min20s-10h29min55s=25s, 则小球从A到C的平均速度: vAC===0.024m/s. 故答案为:0.03m/s;0.024m/s. |