(1)洗衣机正常洗涤时的工作电流I==≈2.7A. (2)洗衣机在额定电压下累积洗涤30min消耗的电能为: W洗=P洗t洗=0.6KW×0.5h=0.3KW•h; 洗衣机在额定电压下累积脱水10min,消耗的电能为: W脱=P脱t脱=0.3KW×h=0.05KW•h; 洗衣机共耗电: W=W洗+W脱=0.3KW•h+0.05KW•h=0.35KW•h. 答:(1)这台洗衣机额定电压下洗涤时,通过的电流约为2.7A; (2)洗衣机在额定电压下累积洗涤30min消耗的电能为0.3KW•h; (3)洗衣机在额定电压下累积脱水10min,消耗的电能为0.05KW•h; (4)洗衣机共耗电0.35KW•h. |