解:(1)从图乙得出,当R2连入的电阻为10Ω时,R1两端的电压为3V,即电压表的示数为3V;
(2)当电压表的示数为2V时,即U1=2V
滑动变阻器连入电阻R2=20Ω
∵R1、R2串联
∴U2=U﹣U1=6V﹣2V=4V
I1=I2= = =0.2A
R1= = =10Ω
(3)由图乙知,滑片P在b端时,滑动变阻器连入的电阻为50Ω
R1两端的电压U1′=1V,即电压表的示数为1V
电阻R1的功率: P1′= = =0.1W.
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