A是一种来自石油的重要的有机化工原料,可以知道A是乙烯,根据BCD,可以知道B是乙醇,C是乙醛,D是乙酸,乙醇可以和乙酸发生酯化反应生成乙酸乙酯E,含有碳碳双键的乙烯可以发生加聚反应生成聚乙烯
![魔方格](http://img.shitiku.com.cn/uploads/allimg/20200107/20200107105520-32471.png)
,可制成多种包装材料. (1)A是CH2=CH2 ,C是CH3CHO,F是
![魔方格](http://img.shitiku.com.cn/uploads/allimg/20200107/20200107105520-32471.png)
,故答案为:CH2=CH2 ;CH3CHO;
![魔方格](http://img.shitiku.com.cn/uploads/allimg/20200107/20200107105520-32471.png)
; (2)乙烯和水发生加成反应得到乙醇,化学方程式为:CH2=CH2+H2OCH3CH2OH,乙醇可以催化氧化为乙醛,即
![魔方格](http://img.shitiku.com.cn/uploads/allimg/20200107/20200107105520-65940.png)
,乙醇可以和乙酸发生酯化反应生成乙酸乙酯,即CH3COOH+HOC2H5
![魔方格](http://img.shitiku.com.cn/uploads/allimg/20200107/20200107105521-83549.png)
CH3COOC2H5+H2O,乙酸乙酯在碱性环境下可以水解生成乙酸钠和醇,即CH3COOCH2CH3+NaOH→CH3COONa+CH3CH2OH,故答案为:CH2=CH2+H2OCH3CH2OH;
![魔方格](http://img.shitiku.com.cn/uploads/allimg/20200107/20200107105520-65940.png)
;CH3COOH+HOC2H5
![魔方格](http://img.shitiku.com.cn/uploads/allimg/20200107/20200107105521-83549.png)
CH3COOC2H5+H2O;CH3COOCH2CH3+NaOH→CH3COONa+CH3CH2OH; (3)含有碳碳双键的化合物丙烯(CH2=CHCH3)可以发生加聚反应,即nCH2=CHCH3
![魔方格](http://img.shitiku.com.cn/uploads/allimg/20200107/20200107105521-53714.png)
,故答案为:nCH2=CHCH3
![魔方格](http://img.shitiku.com.cn/uploads/allimg/20200107/20200107105521-53714.png)
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