若数列{an}满足an+1-an=3,a10=30,则S10=[ ]A.330B.165C.310 D.155
题型:0107 期中题难度:来源:
若数列{an}满足an+1-an=3,a10=30,则S10= |
[ ] |
A.330 B.165 C.310 D.155 |
答案
B |
举一反三
若数列{an}是等差数列,且a6=10,则S11= |
[ ] |
A.95 B.100 C.105 D.110 |
等差数列{an}中,S10=120,那么a1+a10= |
[ ] |
A.12 B.24 C.36 D.48 |
等差数列{an}的前m项和为30,前2m项和为100,则它的前3m项的和为 |
[ ] |
A.130 B.170 C.210 D.260 |
等差数列{an}中,S10=120,那么a2+a9的值是 |
[ ] |
A.12 B.16 C.24 D.48 |
等差数列{an}中,a1+a2+a3=-24,a18+a19+a20=78,则此数列前20项和等于 |
[ ] |
A.160 B.180 C.200 D.220 |
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