log(27)32 × log(64)27+log(9)2 × log(4)根号27=?

题目

log(27)32 × log(64)27+log(9)2 × log(4)根号27=?
log(27)32 × log(64)27+log(9)2 × log(4)根号27=?

答案

log(27)32 × log(64)27+log(9)2 × log(4)根号27
=lg32/lg27×lg27/lg64+lg2/lg9×lg√27/lg4
=lg32/lg64+lg2/lg9×lg√27/lg4
=5/6+1/2×2/（3/2）
=5/6+2/3
=1.5