lim(x趋向于0)(1+sinx-cosx)/(1+sinβx-cosβx)
题目
lim(x趋向于0)(1+sinx-cosx)/(1+sinβx-cosβx)
答案
(1+sinx-cosx)/(1+sinβx-cosβx)=(sinx+2(sin(x/2))^2)/(sinbx+2(sin(bx/2))^2)=[(sin(x/2)+cos(x/2))/(sin(bx/2)+cos(bx/2))]*(sin(x/2)/sin(bx/2))极限与下式的极限相等(cos(x/2)/cos(bx/2))*(sin(x/2)/sin(bx/...
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