解不等式4a³－9a²＋6a－1≥0要过程

题目

解不等式4a³－9a²＋6a－1≥0要过程

答案

4a³－9a²＋6a－1≥04a³-4a²-(5a²-6a+1)≥04a²(a-1)-(5a-1)(a-1)≥0(a-1)(4a²-5a+1)≥0(a-1)(4a-1)(a-1)≥0(a-1)²(4a-1)≥0因为(a-1)²≥0所以4a-1≥0,解得a≥1/4或a=1...