求分式1/(x²+x)+1/(x²+3x+2)+1/(x²+5x+6)+1/(x²+7x+12)+1/(x²+9x+20)的值
题目
求分式1/(x²+x)+1/(x²+3x+2)+1/(x²+5x+6)+1/(x²+7x+12)+1/(x²+9x+20)的值
答案
1/(X)(X+1)+1/(X+1)(X+2)+1/(X+2)(X+3)画到这里我有印象了就是1/2+1/6+1/12就是1-1/2+1/2_1/3+1/3-1/4所以这题的答案是1/X-1/(X+5)=5/(X(X+5)
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