a+x^2=2003,b+x^2=2004,c+x^2=2005,且abc=24,求c/ab+b/ac+a/bc-1/a-1/b-1/c的值.

题目

a+x^2=2003,b+x^2=2004,c+x^2=2005,且abc=24,求c/ab+b/ac+a/bc-1/a-1/b-1/c的值.

答案

a+1=b
b+1=c
a*b*c=24
a=2
b=3
c=4
c/ab+b/ac+a/bc-1/a-1/b-1/c
=1/8