做一道C语言程序设计的题,十万火急!

题目

做一道C语言程序设计的题,十万火急!
已知列车出发时间（输入格式为4位数,如0825）,
甲乙两地距离（单位是千米）,
速度（km/h).求列车到底乙地的时间,
要求格式为（小时：分钟

答案

# include <stdio.h>
int main(void)
{
int time, distance, speed;
int hour, minute;
printf("Please input the start time (such as 0825): ");
scanf("%d",&time);
printf("Please input the distance(km): ");
scanf("%d",&distance);
printf("Please input the speed(km/h): ");
scanf("%d",&speed);

hour=distance/speed;
minute=distance%speed*60/speed;
minute=minute+time%100;
if(minute>=60)
{
minute=minute-60;
hour++;
}
hour=hour+time/100;
printf("Time of arrival:  %d:%02d ",hour,minute);
return 0;
}

没有考虑不能整除的时候,分钟四舍五入的时候,要严谨一定应该考虑,稍微改一下就可以了

下面是考虑了四舍五入的

# include <stdio.h>
int main(void)
{
    int time,hour,minute;
float distance, speed,a;//a用来存放分钟的小数部分,方便四舍五入
    printf("Please input the start time (such as 0825): ");
    scanf("%d",&time);
    printf("Please input the distance(km): "); 
    scanf("%d",&distance);
    printf("Please input the speed(km/h): ");
    scanf("%d",&speed);

    hour=distance/speed;
distance-=hour*speed;

    a=distance*60/speed;
minute=a;
a-=minute;
if(a>=0.5)
minute++;
    minute=minute+time%100;
    if(minute>=60)
    {
        minute=minute-60;
        hour++;
    }
    hour=hour+time/100;
    printf("Time of arrival:  %d:%02d ",hour,minute);
    return 0;
}