求大师计算啊[(-3xy)²*x^4-2x²(3xy²)²*(y/2)]/(-3x²y)²

题目

求大师计算啊[(-3xy)²*x^4-2x²(3xy²)²*(y/2)]/(-3x²y)²
[(-3xy)²*x^4-2x²(3xy²)²*(y/2)]/(-3x²y)²
=[9x²y²*x^4-2x²*9x²y^4*(y/2)]/(9x^4y²
=[x^4(9x²y²)-2x²(9x²y^4)*(y/2)]/(9x^4y²)
=[x^4(9x²y²)-2x²y²(9x²y²)*(y/2)]/(9x²y²)x²
=[(9x²y²)(x^4-2x²y²)*(y/2)]/(9x²y²)x²
=[(x^4-2x²y²)*(y/2)]/x²
=[x²(x²-2y²)*(y/2)]/x²
=(x²-2y²)*(y/2)
=[ ( x² - 2y² ) y ] / 2


对吗
还有更简便的方法吗

答案