设全集U={1,2,3,4,5}若P交Q={2},(CuP)交q={4},(CuR)交(CuQ)={1,5}

题目

设全集U={1,2,3,4,5}若P交Q={2},(CuP)交q={4},(CuR)交(CuQ)={1,5}

答案

题目不全U={1,2,3,4,5}P∩Q={2},说明P,Q只有2是公共元素(CuP)∩Q={4},说明Q有4,P无4 (CuP)∩(CuQ)={1,5} 说明P,Q都无1,5于是：集合P最多由2,3组成,但必须有2集合Q最多由2,3,4组成,但必须有2,4PQ都有3不可能与P∩Q={2...