(log23+lOg427)(log34+log98)=

题目

(log23+lOg427)(log34+log98)=
23中2是底数3是真数,4是底数,3是底数,9是底数

答案

(log23+lOg427)(log34+log98)
=(lg3/lg2+lg27/lg4)(lg4/lg3+lg8/lg9)
=(lg3/lg2+3lg3/2lg2)(2lg2/lg3+3lg2/2lg3)
=(5lg3/2lg2)(7lg2/2lg3)
=(5/2)(7/2)
=35/4