若a=tan(-7π/6）,b=cos23π/4,c=sin(-33π/4）比较大小

题目

若a=tan(-7π/6）,b=cos23π/4,c=sin(-33π/4）比较大小

答案

tan(2π-7π/6)=tan(5π/6)=-√3/3
cos23π/4=cos(6π-π/4)=cos(-π/4)=cos(π/4)=√2/2
sin(-33π/4)=sin(-π/4)=-√2/2
而根3=1.7,根2=1.4
所以cos23π/4>tan(2π-7π/6)>sin(-33π/4)