已知函数f(x)=x的平方+px+q,集合A=(x|f(x)=x),集合B=(x|f(f(x-1)=x+1),当A=(2)时,求集合B.

已知函数f(x)=x的平方+px+q,集合A=(x|f(x)=x),集合B=(x|f(f(x-1)=x+1),当A=(2)时,求集合B.

题目
已知函数f(x)=x的平方+px+q,集合A=(x|f(x)=x),集合B=(x|f(f(x-1)=x+1),当A=(2)时,求集合B.
答案
f(x)=x的平方+px+q
,集合A=(x|f(x)=x),
A=(2)
A的解即为方程f(x)=x的解
x^2+px+q=x
x^2+(p-1)x+q=0
A的解集为x=2
所以方程x^2+(p-1)x+q=0的唯一解为x=2
方程可以写成(x-2)^2=0
x^2-4x+4=0
对比系数可知
p-1=-4 p=-3
q=4
B=(x|f(f(x-1)=x+1),
f(x-1)=(x-1)^2-3(x-1)+4=x^2-5x+8
f(f(x-1))=(x^2-5x+8)^2-3(x^-5x+8)+4=x+1
这个方程貌似比较复杂
最后的解有四个
分别是
5/2+1/6*3^(1/2)*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)+1/6*((-6*(44+12*69^(1/2))^(1/3)*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)-3*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)*(44+12*69^(1/2))^(2/3)+60*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)+18*3^(1/2)*(44+12*69^(1/2))^(1/3))/(44+12*69^(1/2))^(1/3)/((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2))^(1/2)
5/2+1/6*3^(1/2)*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)-1/6*((-6*(44+12*69^(1/2))^(1/3)*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)-3*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)*(44+12*69^(1/2))^(2/3)+60*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)+18*3^(1/2)*(44+12*69^(1/2))^(1/3))/(44+12*69^(1/2))^(1/3)/((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2))^(1/2)
5/2-1/6*3^(1/2)*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)+1/6*i*((6*(44+12*69^(1/2))^(1/3)*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)+3*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)*(44+12*69^(1/2))^(2/3)-60*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)+18*3^(1/2)*(44+12*69^(1/2))^(1/3))/(44+12*69^(1/2))^(1/3)/((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2))^(1/2)
5/2-1/6*3^(1/2)*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)-1/6*i*((6*(44+12*69^(1/2))^(1/3)*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)+3*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)*(44+12*69^(1/2))^(2/3)-60*((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2)+18*3^(1/2)*(44+12*69^(1/2))^(1/3))/(44+12*69^(1/2))^(1/3)/((-(44+12*69^(1/2))^(1/3)+(44+12*69^(1/2))^(2/3)-20)/(44+12*69^(1/2))^(1/3))^(1/2))^(1/2)
举一反三
已知函数f(x)=x,g(x)=alnx,a∈R.若曲线y=f(x)与曲线y=g(x)相交,且在交点处有相同的切线,求a的值和该切线方程.
我想写一篇关于奥巴马的演讲的文章,写哪一篇好呢?为什么好
奥巴马演讲不用看稿子.为什么中国领导演讲要看?
想找英语初三上学期的首字母填空练习……
英语翻译
最新试题
热门考点

超级试练试题库

© 2017-2019 超级试练试题库,All Rights Reserved.