一道一元二次方程题,

题目

一道一元二次方程题,
已知关于x的方程x^2 +mx+ m^2=1,当m=______时,两根互为相反数,当m=________时,两根互为倒数.

答案

x1+x2 = -m/2
x1*x2 = m^2-1
两根互为相反数时,-m/2 = 0,m = 0
互为倒数时,m^2-1 = 1,m = 2^(1/2)