y=sin2x+根号3cos2x-1的最小正周期是()

题目

y=sin2x+根号3cos2x-1的最小正周期是()

答案

y=2(sin2x*1/2+cos2x*√3/2)-1
=2(sin2xcosπ/3+cos2xsinπ/3)-1
=2sin(2x+π/3)-1
所以T=2π/2=π