matlab将一个函数表达式定义成函数

题目

matlab将一个函数表达式定义成函数
x^2+y^2+2*x=2*(x^2+y^2)^1/2;把他定义成一个函数 然后画出来!

答案

>> y=solve('x^2+y^2+2*x = 2*(x^2+y^2)^(1/2)','y')
y =
[ (2-x^2-2*x+2*(1-2*x)^(1/2))^(1/2)]
[ -(2-x^2-2*x+2*(1-2*x)^(1/2))^(1/2)]
[ (2-x^2-2*x-2*(1-2*x)^(1/2))^(1/2)]
[ -(2-x^2-2*x-2*(1-2*x)^(1/2))^(1/2)]
>> ezplot('x^2+y^2+2*x - 2*(x^2+y^2)^(1/2)')