For an arbitrary natural number n,we add 121to it when it is an odd number and have it divided by 2

题目

For an arbitrary natural number n,we add 121to it when it is an odd number and have it divided by 2
(接上）when it is an even number.This is one operation.Now if we perform this operation on 231 successively,whether 100 can appear or not in this process?Why?(请翻译且讲解）

答案

对于任意自然数n,当它是奇数的时候,把它加上121,当它是偶数的时候,把它除以2.这是一种运算.当我们这样连续运算231次后,在这过程中,100是否会出现?为什么?
当然会出现,比如：100*2^231这个数就是啊