如何给：ln[sin(x-1)]求导?

题目

如何给：ln[sin(x-1)]求导?
能写出详细过程吗?辛苦了

答案

（ln[sin(x-1)]）'=1/sin(x-1)*(sin(x-1))'
=1/sin(x-1)*cos(x-1)=cos(x-1)/sin(x-1)